Hello everyone,
For the next planetary season I'm planning to use a Takahashi Mewlon-210 with a QHY 5-III-462C camera. This camera uses the Sony IMX462 CMOS sensor with a pixel edge length of 2.9 µm.
I'm now trying to calculate the optimal focal length / sampling for this setup.
As a rule of thumb, I learned, that the telescopes max. resolution should be covered by 3 pixels in order to achieve optimal sampling. Let's dive into the calculation:
Max. resolution Mewlon-210 = 138 / D
Max. resolution Mewlon-210 = 138 / 210
Max. resolution Mewlon-210 = 0.66" ==> covered by 3 pixels = 0.22'' per pixel.
When I calculate the resolution of the telescope without a barlow lens per pixel, I get the following:
Alpha = (206.265 x d(pixels)) / F
Alpha = (206.265 x 2.9) / 2415
Alpha = 0.25"
The resolution is therefore a little bit lower than desired: 0.25" per pixel < 0.22" per pixel.
What focal length does the system need to achieve 0.22" per pixels?
F = (206.265 x d(pixels) / Alpha
F = (206.265 x 2.9) / 0.22
F = 2719mm
Conclusion: For my understanding, I would not use a Barlow lens for planetary images with this setup. Using a 2x barlow would lead to some heavy oversampling and therefore a "waste" of integration time.
What I don't understand: When I search for planetary images here on AstroBin with this setup, I find a lot of planetary images, which were made with a much longer focal length.
My question: Is my calculation above wrong, am I missing something?
Thank you,
CS, Frank
For the next planetary season I'm planning to use a Takahashi Mewlon-210 with a QHY 5-III-462C camera. This camera uses the Sony IMX462 CMOS sensor with a pixel edge length of 2.9 µm.
I'm now trying to calculate the optimal focal length / sampling for this setup.
As a rule of thumb, I learned, that the telescopes max. resolution should be covered by 3 pixels in order to achieve optimal sampling. Let's dive into the calculation:
Max. resolution Mewlon-210 = 138 / D
Max. resolution Mewlon-210 = 138 / 210
Max. resolution Mewlon-210 = 0.66" ==> covered by 3 pixels = 0.22'' per pixel.
When I calculate the resolution of the telescope without a barlow lens per pixel, I get the following:
Alpha = (206.265 x d(pixels)) / F
Alpha = (206.265 x 2.9) / 2415
Alpha = 0.25"
The resolution is therefore a little bit lower than desired: 0.25" per pixel < 0.22" per pixel.
What focal length does the system need to achieve 0.22" per pixels?
F = (206.265 x d(pixels) / Alpha
F = (206.265 x 2.9) / 0.22
F = 2719mm
Conclusion: For my understanding, I would not use a Barlow lens for planetary images with this setup. Using a 2x barlow would lead to some heavy oversampling and therefore a "waste" of integration time.
What I don't understand: When I search for planetary images here on AstroBin with this setup, I find a lot of planetary images, which were made with a much longer focal length.
My question: Is my calculation above wrong, am I missing something?
Thank you,
CS, Frank