John Tucker:
But the greater speed seen with the F/3 Newt relative to the F/4 when using the same camera still arises because you’ve increased the area of sky each pixel “sees” and thus arises from reduced digital resolution. At least at the first order of analysis, its pretty much equivalent to binning.
John,
You're exactly right to think about what area of the sky is projected onto a pixel by the optics. Now add in one more consideration: the aperture which tells you how many of the photons from that area of the sky are concentrated on that pixel.
For counting photons ignore the rest, it's just a bunch of noise.
https://lambermont.dyndns.org/astro/code/compare-telescopes.html?a&d1=100&l1=500&c1p=2.315&d2=100&l2=1000&c2p=4.63But for the quality of the images produced by your camera you also need to consider the atmospheric seeing, the amount of distortion in the optics that's concentrating the signal onto your pixels and the response of the light sensor behind the pixel. i.e. seeing, strehl ratio, quantum efficiency, and camera noise.
What I do is always start with my site's best seeing. Let's say that it's 1.5".
Then figure out for that seeing what is the optimal sampling (as in the number of pixels laid across that 1.5" blurry star spot). Math says the minimum you need are 2, but reasonable people say about 3.5 or so. For 1.5" seeing that's about 0.43"/px. Now find out what focal length gives you that sampling for your camera. For the most popular IMX533/571/455/411/461 Sony sensors with 3.76u pixels that is 1803mm focal length. Now go buy the biggest/fastest/low distortion optics you can possible afford for that focal length and at the focal plane put the biggest sensor you possible can. Be sure to pair it with the highest quality filters you can find and use the highest quality camera you can find.
Now you have a telescope system that can record everything the sky can offer you at your observing site.
If you want to image smaller/finer things then you have to find a new/better observing site... repeat until you're out of money. :-)